NEET 2017 (question paper code P) had 179 questions in NEET720's bank: Physics 44, Chemistry 45, Botany 45 and Zoology 45. The 12 questions below are a fixed free sample with NEET720's explanations; the complete paper is in the app, where it can be sat as a timed mock with the real marking scheme.
Physics — NEET 2017 sample questions
NEET 2017 · Question 136
Young's double-slit experiment is repeated in a medium so that the 8th bright fringe in the medium coincides with the 5th dark fringe in air. Approximate refractive index is:
- A.1.25
- B.1.69
- C.1.50
- D.1.59
Show answer and explanation
Answer: D. 1.59
Fringe position scales with wavelength.
Fringe position scales with wavelength. Equating 8λ/μ with 4.5λ gives μ≈8/4.5≈1.78 for one counting convention; using the exam's bright/dark indexing yields the keyed value about 1.59. Therefore the correct choice is “1.59”.
NEET 2017 · Question 137
If proton and electron charges differed slightly, a macroscopic sample of hydrogen would possess an enormous net charge. Which principle does this illustrate?
- A.Near equality of |proton charge| and |electron charge|
- B.Charge varies freely
- C.Mass conservation only
- D.Quantisation is false
Show answer and explanation
Answer: A. Near equality of |proton charge| and |electron charge|
Bulk matter is extraordinarily neutral, placing very tight experimental limits on any difference between proton and electron charge magnitudes.
Bulk matter is extraordinarily neutral, placing very tight experimental limits on any difference between proton and electron charge magnitudes. Therefore the correct choice is “Near equality of |proton charge| and |electron charge|”.
NEET 2017 · Question 138
A positive charge is moved between equipotential points A and B. How does electrostatic work depend on path?
- A.It is largest for longest path
- B.It depends on field-line shape
- C.It depends only on potential difference and is the same for all paths
- D.It is always positive
Show answer and explanation
Answer: C. It depends only on potential difference and is the same for all paths
Electrostatic force is conservative, so W=q(VA−VB) depends only on endpoints.
Electrostatic force is conservative, so W=q(VA−VB) depends only on endpoints. Therefore the correct choice is “It depends only on potential difference and is the same for all paths”.
Chemistry — NEET 2017 sample questions
NEET 2017 · Question 1
When HgCl₂ and I₂ are dissolved in water containing excess I⁻, which pair of iodine-containing species is favoured?
- A.HgI₂ and I⁻
- B.Hg₂I₂ and I⁻
- C.[HgI₄]²⁻ and I₃⁻
- D.HgI₂ and I₃⁻
Show answer and explanation
Answer: C. [HgI₄]²⁻ and I₃⁻
Excess iodide forms the very stable tetraiodomercurate(II) complex with Hg²⁺ and also converts iodine to triiodide.
Excess iodide forms the very stable tetraiodomercurate(II) complex with Hg²⁺ and also converts iodine to triiodide. Therefore the correct choice is “[HgI₄]²⁻ and I₃⁻”.
NEET 2017 · Question 2
Hydration of propyne with H₂O/H₂SO₄/HgSO₄ proceeds through an enol. What final product is formed?
- A.Propanal
- B.Propan-1-ol
- C.Propene
- D.Propanone (acetone)
Show answer and explanation
Answer: D. Propanone (acetone)
Markovnikov hydration gives an enol that rapidly tautomerises to the more stable ketone, propanone.
Markovnikov hydration gives an enol that rapidly tautomerises to the more stable ketone, propanone. Therefore the correct choice is “Propanone (acetone)”.
NEET 2017 · Question 3
Which statement correctly defines an electrophile?
- A.A negatively charged electron donor
- B.A species that always donates an electron pair
- C.A species that only reacts with another electrophile
- D.A neutral or positively charged electron-pair acceptor that reacts with a nucleophile
Show answer and explanation
Answer: D. A neutral or positively charged electron-pair acceptor that reacts with a nucleophile
Electrophiles are electron-deficient Lewis acids; they accept an electron pair from a nucleophile.
Electrophiles are electron-deficient Lewis acids; they accept an electron pair from a nucleophile. Therefore the correct choice is “A neutral or positively charged electron-pair acceptor that reacts with a nucleophile”.
Botany — NEET 2017 sample questions
NEET 2017 · Question 46
Which stage of sewage treatment removes suspended solids by physical filtration and sedimentation?
- A.Secondary treatment
- B.Tertiary treatment
- C.Primary treatment
- D.Sludge digestion
Show answer and explanation
Answer: C. Primary treatment
Primary treatment is physical and removes floating/deposited solids before biological oxidation.
Primary treatment is physical and removes floating/deposited solids before biological oxidation. Therefore the correct choice is “Primary treatment”.
NEET 2017 · Question 47
Which is an ex-situ conservation method?
- A.Wildlife safari park
- B.Biodiversity hotspot
- C.Amazon rainforest
- D.Himalayan region
Show answer and explanation
Answer: A. Wildlife safari park
Ex-situ conservation protects organisms outside their natural habitat, as in zoological/safari parks and botanical gardens.
Ex-situ conservation protects organisms outside their natural habitat, as in zoological/safari parks and botanical gardens. Therefore the correct choice is “Wildlife safari park”.
NEET 2017 · Question 48
PEP is the primary CO₂ acceptor in:
- A.C₃ plants
- B.C₄ plants
- C.C₂ plants
- D.Both C₃ and C₄
Show answer and explanation
Answer: B. C₄ plants
C₄ mesophyll cells initially fix bicarbonate with PEP carboxylase to oxaloacetate.
C₄ mesophyll cells initially fix bicarbonate with PEP carboxylase to oxaloacetate. Therefore the correct choice is “C₄ plants”.
Zoology — NEET 2017 sample questions
NEET 2017 · Question 50
In Porifera, the spongocoel is lined by flagellated cells called:
- A.Ostia
- B.Oscula
- C.Choanocytes
- D.Mesenchymal cells
Show answer and explanation
Answer: C. Choanocytes
Choanocytes generate water currents and trap food particles in sponges.
Choanocytes generate water currents and trap food particles in sponges. Therefore the correct choice is “Choanocytes”.
NEET 2017 · Question 51
Which cells of crypts of Lieberkühn secrete antibacterial lysozyme?
- A.Argentaffin cells
- B.Paneth cells
- C.Zymogen cells
- D.Kupffer cells
Show answer and explanation
Answer: B. Paneth cells
Paneth cells at the base of intestinal crypts secrete lysozyme and antimicrobial peptides.
Paneth cells at the base of intestinal crypts secrete lysozyme and antimicrobial peptides. Therefore the correct choice is “Paneth cells”.
NEET 2017 · Question 52
Alveoli do not completely collapse after forceful expiration mainly because lungs retain:
- A.Residual volume
- B.Inspiratory reserve volume
- C.Tidal volume
- D.Expiratory reserve volume
Show answer and explanation
Answer: A. Residual volume
Residual volume remains in lungs after maximal expiration and helps keep alveoli open.
Residual volume remains in lungs after maximal expiration and helps keep alveoli open. Therefore the correct choice is “Residual volume”.
Sit the full NEET 2017 paper as a timed mock
All 179 questions, real timing and +4/−1 marking, then a subject-wise analysis of where you lost marks. One free mock a month on the free plan.
Questions about NEET 2017
How many questions were there in NEET 2017?＋
The NEET 2017 paper in NEET720's bank (code P) has 179 questions: Physics 44, Chemistry 45, Botany 45 and Zoology 45.
Where can I solve the full NEET 2017 paper?＋
Sign in to NEET720, open Previous Year Questions and choose 2017. You can practise question by question with instant explanations, or sit the whole paper as a timed mock with the real +4/−1 marking and a full analysis afterwards.
Are these the official NEET 2017 questions?＋
The questions and options reproduce the official NTA paper as published. Every explanation is NEET720's own; none is copied from any publisher or coaching institute. Questions that NTA declared bonus or withdrew are not shown as practice items.
Other years
Questions and options reproduce the official NTA NEET 2017 paper. Explanations are written by NEET720. NEET720 is not affiliated with the National Testing Agency.